Base | Representation |
---|---|
bin | 101111101101010001… |
… | …100101011010000001 |
3 | 11220012222201111011002 |
4 | 233231101211122001 |
5 | 1314402203400423 |
6 | 35311015101345 |
7 | 3462262066415 |
oct | 575521453201 |
9 | 156188644132 |
10 | 51225450113 |
11 | 1a7a7481942 |
12 | 9b17371855 |
13 | 4aa4905236 |
14 | 269d3a6d45 |
15 | 14ec25b228 |
hex | bed465681 |
51225450113 has 2 divisors, whose sum is σ = 51225450114. Its totient is φ = 51225450112.
The previous prime is 51225450103. The next prime is 51225450151. The reversal of 51225450113 is 31105452215.
51225450113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32781637249 + 18443812864 = 181057^2 + 135808^2 .
It is a cyclic number.
It is not a de Polignac number, because 51225450113 - 28 = 51225449857 is a prime.
It is not a weakly prime, because it can be changed into another prime (51225450103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25612725056 + 25612725057.
It is an arithmetic number, because the mean of its divisors is an integer number (25612725057).
Almost surely, 251225450113 is an apocalyptic number.
It is an amenable number.
51225450113 is a deficient number, since it is larger than the sum of its proper divisors (1).
51225450113 is an equidigital number, since it uses as much as digits as its factorization.
51225450113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6000, while the sum is 29.
The spelling of 51225450113 in words is "fifty-one billion, two hundred twenty-five million, four hundred fifty thousand, one hundred thirteen".
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