Base | Representation |
---|---|
bin | 111010001111011110011110… |
… | …1110111110100001000111010 |
3 | 2111011220102222122112212201122 |
4 | 1310132330331313310020322 |
5 | 1014122012301142004432 |
6 | 5013323324001345242 |
7 | 212623325351151266 |
oct | 16436747567641072 |
9 | 2434812878485648 |
10 | 512300442141242 |
11 | 139264440a42157 |
12 | 4955b311638222 |
13 | 18cb1955689ac1 |
14 | 907168bb910a6 |
15 | 3e3619bc17612 |
hex | 1d1ef3ddf423a |
512300442141242 has 8 divisors (see below), whose sum is σ = 768455210522100. Its totient is φ = 256148705300544.
The previous prime is 512300442141221. The next prime is 512300442141317. The reversal of 512300442141242 is 242141244003215.
It can be written as a sum of positive squares in 2 ways, for example, as 455455311277201 + 56845130864041 = 21341399^2 + 7539571^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×5123004421412422 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 757462517 + ... + 758138552.
Almost surely, 2512300442141242 is an apocalyptic number.
512300442141242 is a deficient number, since it is larger than the sum of its proper divisors (256154768380858).
512300442141242 is a wasteful number, since it uses less digits than its factorization.
512300442141242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1515770080.
The product of its (nonzero) digits is 61440, while the sum is 35.
Adding to 512300442141242 its reverse (242141244003215), we get a palindrome (754441686144457).
The spelling of 512300442141242 in words is "five hundred twelve trillion, three hundred billion, four hundred forty-two million, one hundred forty-one thousand, two hundred forty-two".
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