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5123234524433 = 94750051108089
BaseRepresentation
bin100101010001101100010…
…0100101110110100010001
3200010202222000121121021212
41022203120210232310101
51132414341014240213
614521325332025505
71036066345636004
oct112433044566421
920122860547255
105123234524433
1116a582a365773
126a8b00a62295
132b21714175cc
14139d7450353b
158d4016449a8
hex4a8d892ed11

5123234524433 has 8 divisors (see below), whose sum is σ = 5128794404640. Its totient is φ = 5117674962400.

The previous prime is 5123234524367. The next prime is 5123234524523. The reversal of 5123234524433 is 3344254323215.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5123234524433 - 210 = 5123234523409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5123234524333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47344253 + ... + 47452341.

It is an arithmetic number, because the mean of its divisors is an integer number (641099300580).

Almost surely, 25123234524433 is an apocalyptic number.

It is an amenable number.

5123234524433 is a deficient number, since it is larger than the sum of its proper divisors (5559880207).

5123234524433 is a wasteful number, since it uses less digits than its factorization.

5123234524433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159087.

The product of its digits is 1036800, while the sum is 41.

Adding to 5123234524433 its reverse (3344254323215), we get a palindrome (8467488847648).

The spelling of 5123234524433 in words is "five trillion, one hundred twenty-three billion, two hundred thirty-four million, five hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 947 50051 108089 47398297 102360283 5409962539 5123234524433