Base | Representation |
---|---|
bin | 111010010001000111000100… |
… | …1110011010101100110000001 |
3 | 2111012200220202021000120101012 |
4 | 1310202032021303111212001 |
5 | 1014134202302402212421 |
6 | 5014014432020250305 |
7 | 212645466430253264 |
oct | 16442161163254601 |
9 | 2435626667016335 |
10 | 512525054335361 |
11 | 139340722743051 |
12 | 49596957840995 |
13 | 18cc9b9ca80342 |
14 | 907c4b890acdb |
15 | 3e3be45ca895b |
hex | 1d22389cd5981 |
512525054335361 has 2 divisors, whose sum is σ = 512525054335362. Its totient is φ = 512525054335360.
The previous prime is 512525054335223. The next prime is 512525054335457. The reversal of 512525054335361 is 163533450525215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 510651525760000 + 1873528575361 = 22597600^2 + 1368769^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-512525054335361 is a prime.
It is not a weakly prime, because it can be changed into another prime (512525054335661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256262527167680 + 256262527167681.
It is an arithmetic number, because the mean of its divisors is an integer number (256262527167681).
Almost surely, 2512525054335361 is an apocalyptic number.
It is an amenable number.
512525054335361 is a deficient number, since it is larger than the sum of its proper divisors (1).
512525054335361 is an equidigital number, since it uses as much as digits as its factorization.
512525054335361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100000, while the sum is 50.
The spelling of 512525054335361 in words is "five hundred twelve trillion, five hundred twenty-five billion, fifty-four million, three hundred thirty-five thousand, three hundred sixty-one".
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