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51254214593 is a prime number
BaseRepresentation
bin101111101110111111…
…010011111111000001
311220021222211212121012
4233232333103333001
51314432034331333
635313523410305
73463061431031
oct575677237701
9156258755535
1051254214593
111a81173903a
129b24b23995
134aaa866a3a
1426a31338c1
1514eea3de48
hexbeefd3fc1

51254214593 has 2 divisors, whose sum is σ = 51254214594. Its totient is φ = 51254214592.

The previous prime is 51254214587. The next prime is 51254214607. The reversal of 51254214593 is 39541245215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47824003969 + 3430210624 = 218687^2 + 58568^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51254214593 is a prime.

It is a super-4 number, since 4×512542145934 (a number of 44 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 51254214593.

It is not a weakly prime, because it can be changed into another prime (51254514593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25627107296 + 25627107297.

It is an arithmetic number, because the mean of its divisors is an integer number (25627107297).

Almost surely, 251254214593 is an apocalyptic number.

It is an amenable number.

51254214593 is a deficient number, since it is larger than the sum of its proper divisors (1).

51254214593 is an equidigital number, since it uses as much as digits as its factorization.

51254214593 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 216000, while the sum is 41.

The spelling of 51254214593 in words is "fifty-one billion, two hundred fifty-four million, two hundred fourteen thousand, five hundred ninety-three".