Base | Representation |
---|---|
bin | 1001100011000111… |
… | …10010000101101001 |
3 | 111020021021200101211 |
4 | 10301203302011221 |
5 | 40444331243311 |
6 | 2204405113121 |
7 | 241015642132 |
oct | 46143620551 |
9 | 14207250354 |
10 | 5126431081 |
11 | 21a0811602 |
12 | bb09b87a1 |
13 | 6390c7a95 |
14 | 368bb2c89 |
15 | 2000cc821 |
hex | 1318f2169 |
5126431081 has 2 divisors, whose sum is σ = 5126431082. Its totient is φ = 5126431080.
The previous prime is 5126431019. The next prime is 5126431129. The reversal of 5126431081 is 1801346215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4380321856 + 746109225 = 66184^2 + 27315^2 .
It is a cyclic number.
It is not a de Polignac number, because 5126431081 - 223 = 5118042473 is a prime.
It is a super-2 number, since 2×51264310812 = 52560591256485657122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5126431001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2563215540 + 2563215541.
It is an arithmetic number, because the mean of its divisors is an integer number (2563215541).
Almost surely, 25126431081 is an apocalyptic number.
It is an amenable number.
5126431081 is a deficient number, since it is larger than the sum of its proper divisors (1).
5126431081 is an equidigital number, since it uses as much as digits as its factorization.
5126431081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 31.
The square root of 5126431081 is about 71599.0997219937. The cubic root of 5126431081 is about 1724.2690825958.
Adding to 5126431081 its reverse (1801346215), we get a palindrome (6927777296).
The spelling of 5126431081 in words is "five billion, one hundred twenty-six million, four hundred thirty-one thousand, eighty-one".
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