Base | Representation |
---|---|
bin | 101111110000001110… |
… | …111000100001110001 |
3 | 11220100110002121211211 |
4 | 233300032320201301 |
5 | 1320002404324044 |
6 | 35315550440121 |
7 | 3463433635432 |
oct | 576016704161 |
9 | 156313077754 |
10 | 51275073649 |
11 | 1a822495828 |
12 | 9b2bb03041 |
13 | 4ab1c8b187 |
14 | 26a5c03489 |
15 | 15017ae634 |
hex | bf03b8871 |
51275073649 has 2 divisors, whose sum is σ = 51275073650. Its totient is φ = 51275073648.
The previous prime is 51275073511. The next prime is 51275073659. The reversal of 51275073649 is 94637057215.
51275073649 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51275073600 + 49 = 226440^2 + 7^2 .
It is a cyclic number.
It is not a de Polignac number, because 51275073649 - 215 = 51275040881 is a prime.
It is not a weakly prime, because it can be changed into another prime (51275073659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25637536824 + 25637536825.
It is an arithmetic number, because the mean of its divisors is an integer number (25637536825).
Almost surely, 251275073649 is an apocalyptic number.
It is an amenable number.
51275073649 is a deficient number, since it is larger than the sum of its proper divisors (1).
51275073649 is an equidigital number, since it uses as much as digits as its factorization.
51275073649 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1587600, while the sum is 49.
Subtracting from 51275073649 its sum of digits (49), we obtain a square (51275073600 = 2264402).
It can be divided in two parts, 512750736 and 49, that multiplied together give a square (25124786064 = 1585082).
The spelling of 51275073649 in words is "fifty-one billion, two hundred seventy-five million, seventy-three thousand, six hundred forty-nine".
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