Base | Representation |
---|---|
bin | 100101010011101100101… |
… | …0110100100000111000001 |
3 | 200011012002020221020100020 |
4 | 1022213121112210013001 |
5 | 1133002201343230243 |
6 | 14523321024044053 |
7 | 1036311166410051 |
oct | 112473126440701 |
9 | 20135066836306 |
10 | 5127542555073 |
11 | 16a7640108974 |
12 | 6a9903763629 |
13 | 2b26a9ab9173 |
14 | 13a26271b561 |
15 | 8d5a4963283 |
hex | 4a9d95a41c1 |
5127542555073 has 4 divisors (see below), whose sum is σ = 6836723406768. Its totient is φ = 3418361703380.
The previous prime is 5127542555059. The next prime is 5127542555129. The reversal of 5127542555073 is 3705552457215.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5127542555073 - 25 = 5127542555041 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5127542555173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 854590425843 + ... + 854590425848.
It is an arithmetic number, because the mean of its divisors is an integer number (1709180851692).
Almost surely, 25127542555073 is an apocalyptic number.
It is an amenable number.
5127542555073 is a deficient number, since it is larger than the sum of its proper divisors (1709180851695).
5127542555073 is a wasteful number, since it uses less digits than its factorization.
5127542555073 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1709180851694.
The product of its (nonzero) digits is 7350000, while the sum is 51.
The spelling of 5127542555073 in words is "five trillion, one hundred twenty-seven billion, five hundred forty-two million, five hundred fifty-five thousand, seventy-three".
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