Base | Representation |
---|---|
bin | 100101010011111110000… |
… | …1110100011000001010011 |
3 | 200011020121000220102221122 |
4 | 1022213330032203001103 |
5 | 1133004401134443034 |
6 | 14523455044512455 |
7 | 1036331532603524 |
oct | 112477416430123 |
9 | 20136530812848 |
10 | 5128127656019 |
11 | 16a791040a975 |
12 | 6a9a476ab72b |
13 | 2b2771099344 |
14 | 13a2ba30684b |
15 | 8d5daedb62e |
hex | 4a9fc3a3053 |
5128127656019 has 2 divisors, whose sum is σ = 5128127656020. Its totient is φ = 5128127656018.
The previous prime is 5128127655997. The next prime is 5128127656037. The reversal of 5128127656019 is 9106567218215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5128127656019 - 240 = 4028616028243 is a prime.
It is a super-3 number, since 3×51281276560193 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5128127656919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2564063828009 + 2564063828010.
It is an arithmetic number, because the mean of its divisors is an integer number (2564063828010).
Almost surely, 25128127656019 is an apocalyptic number.
5128127656019 is a deficient number, since it is larger than the sum of its proper divisors (1).
5128127656019 is an equidigital number, since it uses as much as digits as its factorization.
5128127656019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1814400, while the sum is 53.
The spelling of 5128127656019 in words is "five trillion, one hundred twenty-eight billion, one hundred twenty-seven million, six hundred fifty-six thousand, nineteen".
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