Base | Representation |
---|---|
bin | 100101010100110111010… |
… | …0001110010001000111011 |
3 | 200011102112200021220202012 |
4 | 1022221232201302020323 |
5 | 1133022313044120212 |
6 | 14524413230400135 |
7 | 1036430206404233 |
oct | 112515641621073 |
9 | 20142480256665 |
10 | 5130045301307 |
11 | 16a8704918193 |
12 | 6aa2a196004b |
13 | 2b29b846a5b4 |
14 | 13a41cc84cc3 |
15 | 8d69e532922 |
hex | 4aa6e87223b |
5130045301307 has 2 divisors, whose sum is σ = 5130045301308. Its totient is φ = 5130045301306.
The previous prime is 5130045301291. The next prime is 5130045301351. The reversal of 5130045301307 is 7031035400315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5130045301307 - 24 = 5130045301291 is a prime.
It is not a weakly prime, because it can be changed into another prime (5130045301607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565022650653 + 2565022650654.
It is an arithmetic number, because the mean of its divisors is an integer number (2565022650654).
Almost surely, 25130045301307 is an apocalyptic number.
5130045301307 is a deficient number, since it is larger than the sum of its proper divisors (1).
5130045301307 is an equidigital number, since it uses as much as digits as its factorization.
5130045301307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18900, while the sum is 32.
The spelling of 5130045301307 in words is "five trillion, one hundred thirty billion, forty-five million, three hundred one thousand, three hundred seven".
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