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51301401 = 317100467
BaseRepresentation
bin1100001110110…
…0110000011001
310120112101021220
43003230300121
5101113121101
65031322253
71162024524
oct303546031
9116471256
1051301401
1126a5a558
1215220389
13a822878
146b55bbb
154785636
hex30ecc19

51301401 has 4 divisors (see below), whose sum is σ = 68401872. Its totient is φ = 34200932.

The previous prime is 51301381. The next prime is 51301421. The reversal of 51301401 is 10410315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (51301381) and next prime (51301421).

It is a cyclic number.

It is not a de Polignac number, because 51301401 - 210 = 51300377 is a prime.

It is not an unprimeable number, because it can be changed into a prime (51301421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8550231 + ... + 8550236.

It is an arithmetic number, because the mean of its divisors is an integer number (17100468).

Almost surely, 251301401 is an apocalyptic number.

It is an amenable number.

51301401 is a deficient number, since it is larger than the sum of its proper divisors (17100471).

51301401 is a wasteful number, since it uses less digits than its factorization.

51301401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17100470.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 51301401 is about 7162.4996335078. The cubic root of 51301401 is about 371.5720813647.

Adding to 51301401 its reverse (10410315), we get a palindrome (61711716).

The spelling of 51301401 in words is "fifty-one million, three hundred one thousand, four hundred one".

Divisors: 1 3 17100467 51301401