Base | Representation |
---|---|
bin | 1110111011101000011… |
… | …00011010100111101001 |
3 | 1211001021101001211011122 |
4 | 13131310030122213221 |
5 | 31401211413120131 |
6 | 1031405301105025 |
7 | 52031604315623 |
oct | 7356414324751 |
9 | 1731241054148 |
10 | 513050520041 |
11 | 188646709354 |
12 | 835236b8175 |
13 | 394c3b2a797 |
14 | 1ab9057dc13 |
15 | d52b713d7b |
hex | 777431a9e9 |
513050520041 has 2 divisors, whose sum is σ = 513050520042. Its totient is φ = 513050520040.
The previous prime is 513050519987. The next prime is 513050520053. The reversal of 513050520041 is 140025050315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 328168579600 + 184881940441 = 572860^2 + 429979^2 .
It is a cyclic number.
It is not a de Polignac number, because 513050520041 - 26 = 513050519977 is a prime.
It is a super-2 number, since 2×5130505200412 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (513050520071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256525260020 + 256525260021.
It is an arithmetic number, because the mean of its divisors is an integer number (256525260021).
Almost surely, 2513050520041 is an apocalyptic number.
It is an amenable number.
513050520041 is a deficient number, since it is larger than the sum of its proper divisors (1).
513050520041 is an equidigital number, since it uses as much as digits as its factorization.
513050520041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 26.
Adding to 513050520041 its reverse (140025050315), we get a palindrome (653075570356).
The spelling of 513050520041 in words is "five hundred thirteen billion, fifty million, five hundred twenty thousand, forty-one".
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