5131100113 has 4 divisors (see below), whose sum is σ = 5136136560. Its totient is φ = 5126063668.

The previous prime is 5131100099. The next prime is 5131100131. The reversal of 5131100113 is 3110011315.

5131100113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5131100113 - 2²⁵ = 5097545681 is a prime.

It is a super-2 number, since 2×5131100113² = 52656376739257225538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5131100213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2516695 + ... + 2518732.

It is an arithmetic number, because the mean of its divisors is an integer number (1284034140).

Almost surely, 2^5131100113 is an apocalyptic number.

It is an amenable number.

5131100113 is a deficient number, since it is larger than the sum of its proper divisors (5036447).

5131100113 is a wasteful number, since it uses less digits than its factorization.

5131100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5036446.

The product of its (nonzero) digits is 45, while the sum is 16.

The square root of 5131100113 is about 71631.6976833580. The cubic root of 5131100113 is about 1724.7923982328.

Adding to 5131100113 its reverse (3110011315), we get a palindrome (8241111428).

The spelling of 5131100113 in words is "five billion, one hundred thirty-one million, one hundred thousand, one hundred thirteen".