Base | Representation |
---|---|
bin | 1110111011110101111… |
… | …11001110110101010001 |
3 | 1211001120022112211022121 |
4 | 13131322333032311101 |
5 | 31401430103120101 |
6 | 1031424452134241 |
7 | 52034460213553 |
oct | 7357277166521 |
9 | 1731508484277 |
10 | 513164504401 |
11 | 1886a4a914aa |
12 | 83555907381 |
13 | 39511629553 |
14 | 1aba17714d3 |
15 | d53672c0a1 |
hex | 777afced51 |
513164504401 has 2 divisors, whose sum is σ = 513164504402. Its totient is φ = 513164504400.
The previous prime is 513164504309. The next prime is 513164504407. The reversal of 513164504401 is 104405461315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 491087002176 + 22077502225 = 700776^2 + 148585^2 .
It is a cyclic number.
It is not a de Polignac number, because 513164504401 - 217 = 513164373329 is a prime.
It is not a weakly prime, because it can be changed into another prime (513164504407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256582252200 + 256582252201.
It is an arithmetic number, because the mean of its divisors is an integer number (256582252201).
Almost surely, 2513164504401 is an apocalyptic number.
It is an amenable number.
513164504401 is a deficient number, since it is larger than the sum of its proper divisors (1).
513164504401 is an equidigital number, since it uses as much as digits as its factorization.
513164504401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 513164504401 its reverse (104405461315), we get a palindrome (617569965716).
The spelling of 513164504401 in words is "five hundred thirteen billion, one hundred sixty-four million, five hundred four thousand, four hundred one".
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