Base | Representation |
---|---|
bin | 1110111011111100111… |
… | …10110110100110111001 |
3 | 1211001201101212002020221 |
4 | 13131332132312212321 |
5 | 31402040110003213 |
6 | 1031434344420041 |
7 | 52036101405424 |
oct | 7357636664671 |
9 | 1731641762227 |
10 | 513223125433 |
11 | 188725090337 |
12 | 83571477621 |
13 | 39520812955 |
14 | 1aba94709bb |
15 | d53b95b38d |
hex | 777e7b69b9 |
513223125433 has 2 divisors, whose sum is σ = 513223125434. Its totient is φ = 513223125432.
The previous prime is 513223125427. The next prime is 513223125479. The reversal of 513223125433 is 334521322315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 258630222249 + 254592903184 = 508557^2 + 504572^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513223125433 is a prime.
It is not a weakly prime, because it can be changed into another prime (513223123433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256611562716 + 256611562717.
It is an arithmetic number, because the mean of its divisors is an integer number (256611562717).
Almost surely, 2513223125433 is an apocalyptic number.
It is an amenable number.
513223125433 is a deficient number, since it is larger than the sum of its proper divisors (1).
513223125433 is an equidigital number, since it uses as much as digits as its factorization.
513223125433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 64800, while the sum is 34.
Adding to 513223125433 its reverse (334521322315), we get a palindrome (847744447748).
The spelling of 513223125433 in words is "five hundred thirteen billion, two hundred twenty-three million, one hundred twenty-five thousand, four hundred thirty-three".
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