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5133140545051 = 29317519251007
BaseRepresentation
bin100101010110010011100…
…0001001100111000011011
3200011201112101112120221101
41022230213001030320123
51133100132434420201
614530044320252231
71036600002502411
oct112544701147033
920151471476841
105133140545051
1116a9a53020672
126aaa06471077
132b308c7bb77c
1413a633da12b1
158d7d113bd01
hex4ab2704ce1b

5133140545051 has 4 divisors (see below), whose sum is σ = 5150659796352. Its totient is φ = 5115621293752.

The previous prime is 5133140544997. The next prime is 5133140545069. The reversal of 5133140545051 is 1505450413315.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5133140545051 - 235 = 5098780806683 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5133140545051.

It is not an unprimeable number, because it can be changed into a prime (5133140545751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8759625211 + ... + 8759625796.

It is an arithmetic number, because the mean of its divisors is an integer number (1287664949088).

Almost surely, 25133140545051 is an apocalyptic number.

5133140545051 is a deficient number, since it is larger than the sum of its proper divisors (17519251301).

5133140545051 is a wasteful number, since it uses less digits than its factorization.

5133140545051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17519251300.

The product of its (nonzero) digits is 90000, while the sum is 37.

Adding to 5133140545051 its reverse (1505450413315), we get a palindrome (6638590958366).

The spelling of 5133140545051 in words is "five trillion, one hundred thirty-three billion, one hundred forty million, five hundred forty-five thousand, fifty-one".

Divisors: 1 293 17519251007 5133140545051