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5133275551441 is a prime number
BaseRepresentation
bin100101010110010111100…
…0100001101011011010001
3200011201212210120121220001
41022230233010031123101
51133100422020121231
614530105542050001
71036603232154142
oct112545704153321
920151783517801
105133275551441
1116aa0122519a4
126aaa43719901
132b30b176abcb
1413a647ca5ac9
158d7dce08b61
hex4ab2f10d6d1

5133275551441 has 2 divisors, whose sum is σ = 5133275551442. Its totient is φ = 5133275551440.

The previous prime is 5133275551387. The next prime is 5133275551463. The reversal of 5133275551441 is 1441555723315.

5133275551441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4856752070416 + 276523481025 = 2203804^2 + 525855^2 .

It is a cyclic number.

It is not a de Polignac number, because 5133275551441 - 211 = 5133275549393 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5133275551391 and 5133275551400.

It is not a weakly prime, because it can be changed into another prime (5133275551741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566637775720 + 2566637775721.

It is an arithmetic number, because the mean of its divisors is an integer number (2566637775721).

Almost surely, 25133275551441 is an apocalyptic number.

It is an amenable number.

5133275551441 is a deficient number, since it is larger than the sum of its proper divisors (1).

5133275551441 is an equidigital number, since it uses as much as digits as its factorization.

5133275551441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1260000, while the sum is 46.

The spelling of 5133275551441 in words is "five trillion, one hundred thirty-three billion, two hundred seventy-five million, five hundred fifty-one thousand, four hundred forty-one".