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5133333843347 is a prime number
BaseRepresentation
bin100101010110011001010…
…0010100100110110010011
3200011202000212021011100112
41022230302202210312103
51133101031430441342
614530115423311535
71036604540505323
oct112546242446623
920152025234315
105133333843347
1116aa042146526
126aaa5b14b5ab
132b30c086a568
1413a65191b283
158d7e30c0682
hex4ab328a4d93

5133333843347 has 2 divisors, whose sum is σ = 5133333843348. Its totient is φ = 5133333843346.

The previous prime is 5133333843263. The next prime is 5133333843373. The reversal of 5133333843347 is 7433483333315.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5133333843347 - 212 = 5133333839251 is a prime.

It is a super-2 number, since 2×51333338433472 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5133333843295 and 5133333843304.

It is not a weakly prime, because it can be changed into another prime (5133333843377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566666921673 + 2566666921674.

It is an arithmetic number, because the mean of its divisors is an integer number (2566666921674).

Almost surely, 25133333843347 is an apocalyptic number.

5133333843347 is a deficient number, since it is larger than the sum of its proper divisors (1).

5133333843347 is an equidigital number, since it uses as much as digits as its factorization.

5133333843347 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9797760, while the sum is 50.

The spelling of 5133333843347 in words is "five trillion, one hundred thirty-three billion, three hundred thirty-three million, eight hundred forty-three thousand, three hundred forty-seven".