Base | Representation |
---|---|
bin | 100101010110011001010… |
… | …0010100100110110010011 |
3 | 200011202000212021011100112 |
4 | 1022230302202210312103 |
5 | 1133101031430441342 |
6 | 14530115423311535 |
7 | 1036604540505323 |
oct | 112546242446623 |
9 | 20152025234315 |
10 | 5133333843347 |
11 | 16aa042146526 |
12 | 6aaa5b14b5ab |
13 | 2b30c086a568 |
14 | 13a65191b283 |
15 | 8d7e30c0682 |
hex | 4ab328a4d93 |
5133333843347 has 2 divisors, whose sum is σ = 5133333843348. Its totient is φ = 5133333843346.
The previous prime is 5133333843263. The next prime is 5133333843373. The reversal of 5133333843347 is 7433483333315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5133333843347 - 212 = 5133333839251 is a prime.
It is a super-2 number, since 2×51333338433472 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5133333843295 and 5133333843304.
It is not a weakly prime, because it can be changed into another prime (5133333843377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566666921673 + 2566666921674.
It is an arithmetic number, because the mean of its divisors is an integer number (2566666921674).
Almost surely, 25133333843347 is an apocalyptic number.
5133333843347 is a deficient number, since it is larger than the sum of its proper divisors (1).
5133333843347 is an equidigital number, since it uses as much as digits as its factorization.
5133333843347 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9797760, while the sum is 50.
The spelling of 5133333843347 in words is "five trillion, one hundred thirty-three billion, three hundred thirty-three million, eight hundred forty-three thousand, three hundred forty-seven".
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