Base | Representation |
---|---|
bin | 10111010101111111111101… |
… | …00001011110001110101011 |
3 | 20201202102112121022012210001 |
4 | 23222333332201132032223 |
5 | 23212021323112420211 |
6 | 301102125524403431 |
7 | 13545501052340524 |
oct | 1352777641361653 |
9 | 221672477265701 |
10 | 51333424341931 |
11 | 153a1423866066 |
12 | 5910917b46577 |
13 | 228494b47bb24 |
14 | c9679dd0384b |
15 | 5e0478123ac1 |
hex | 2eaffe85e3ab |
51333424341931 has 2 divisors, whose sum is σ = 51333424341932. Its totient is φ = 51333424341930.
The previous prime is 51333424341919. The next prime is 51333424341973. The reversal of 51333424341931 is 13914342433315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51333424341931 - 215 = 51333424309163 is a prime.
It is a super-2 number, since 2×513334243419312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51333424311931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25666712170965 + 25666712170966.
It is an arithmetic number, because the mean of its divisors is an integer number (25666712170966).
Almost surely, 251333424341931 is an apocalyptic number.
51333424341931 is a deficient number, since it is larger than the sum of its proper divisors (1).
51333424341931 is an equidigital number, since it uses as much as digits as its factorization.
51333424341931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1399680, while the sum is 46.
The spelling of 51333424341931 in words is "fifty-one trillion, three hundred thirty-three billion, four hundred twenty-four million, three hundred forty-one thousand, nine hundred thirty-one".
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