Base | Representation |
---|---|
bin | 101111110011101111… |
… | …101001011001001001 |
3 | 11220111112222002110011 |
4 | 233303233221121021 |
5 | 1320113000302212 |
6 | 35325453351521 |
7 | 3465050515153 |
oct | 576357513111 |
9 | 156445862404 |
10 | 51333994057 |
11 | 1a852779585 |
12 | 9b477985a1 |
13 | 4ac124a918 |
14 | 26ad97dad3 |
15 | 1506a4c4a7 |
hex | bf3be9649 |
51333994057 has 8 divisors (see below), whose sum is σ = 51429340352. Its totient is φ = 51238710000.
The previous prime is 51333994039. The next prime is 51333994073. The reversal of 51333994057 is 75049933315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51333994057 - 211 = 51333992009 is a prime.
It is a super-2 number, since 2×513339940572 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 51333994057.
It is not an unprimeable number, because it can be changed into a prime (51333994157) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1835932 + ... + 1863682.
It is an arithmetic number, because the mean of its divisors is an integer number (6428667544).
Almost surely, 251333994057 is an apocalyptic number.
It is an amenable number.
51333994057 is a deficient number, since it is larger than the sum of its proper divisors (95346295).
51333994057 is a wasteful number, since it uses less digits than its factorization.
51333994057 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31119.
The product of its (nonzero) digits is 1530900, while the sum is 49.
The spelling of 51333994057 in words is "fifty-one billion, three hundred thirty-three million, nine hundred ninety-four thousand, fifty-seven".
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