Base | Representation |
---|---|
bin | 10111010110000001000111… |
… | …00001010000000110010011 |
3 | 20201202111010212020222220001 |
4 | 23223000203201100012103 |
5 | 23212024111012303133 |
6 | 301102311300230431 |
7 | 13545522330240112 |
oct | 1353004341200623 |
9 | 221674125228801 |
10 | 51334045041043 |
11 | 153a1712171536 |
12 | 5910a6b99b417 |
13 | 2284a19c440cb |
14 | c9681c517c79 |
15 | 5e04b287e87d |
hex | 2eb023850193 |
51334045041043 has 4 divisors (see below), whose sum is σ = 51334366796208. Its totient is φ = 51333723285880.
The previous prime is 51334045041031. The next prime is 51334045041061. The reversal of 51334045041043 is 34014054043315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51334045041043 - 25 = 51334045041011 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 51334045040993 and 51334045041011.
It is not an unprimeable number, because it can be changed into a prime (51334045041023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160638148 + ... + 160957393.
It is an arithmetic number, because the mean of its divisors is an integer number (12833591699052).
Almost surely, 251334045041043 is an apocalyptic number.
51334045041043 is a deficient number, since it is larger than the sum of its proper divisors (321755165).
51334045041043 is a wasteful number, since it uses less digits than its factorization.
51334045041043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 321755164.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 51334045041043 its reverse (34014054043315), we get a palindrome (85348099084358).
The spelling of 51334045041043 in words is "fifty-one trillion, three hundred thirty-four billion, forty-five million, forty-one thousand, forty-three".
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