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5133441044057 = 5987007475323
BaseRepresentation
bin100101010110011100011…
…1011100000111001011001
3200011202022022222112002012
41022230320323200321121
51133101241401402212
614530134213115305
71036610311630664
oct112547073407131
920152268875065
105133441044057
1116aa097705a57
126aaa8b028b35
132b3109b32731
1413a661c646db
158d7ec6e8922
hex4ab38ee0e59

5133441044057 has 4 divisors (see below), whose sum is σ = 5220448519440. Its totient is φ = 5046433568676.

The previous prime is 5133441044009. The next prime is 5133441044111. The reversal of 5133441044057 is 7504401443315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5133441044057 - 210 = 5133441043033 is a prime.

It is a super-3 number, since 3×51334410440573 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5133441004057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43503737603 + ... + 43503737720.

It is an arithmetic number, because the mean of its divisors is an integer number (1305112129860).

Almost surely, 25133441044057 is an apocalyptic number.

It is an amenable number.

5133441044057 is a deficient number, since it is larger than the sum of its proper divisors (87007475383).

5133441044057 is an equidigital number, since it uses as much as digits as its factorization.

5133441044057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87007475382.

The product of its (nonzero) digits is 403200, while the sum is 41.

The spelling of 5133441044057 in words is "five trillion, one hundred thirty-three billion, four hundred forty-one million, forty-four thousand, fifty-seven".

Divisors: 1 59 87007475323 5133441044057