Base | Representation |
---|---|
bin | 1001100100000001… |
… | …00101000100110001 |
3 | 111020210111012111200 |
4 | 10302000211010301 |
5 | 41003244324303 |
6 | 2205235001413 |
7 | 241140052404 |
oct | 46200450461 |
9 | 14223435450 |
10 | 5133979953 |
11 | 21a4aa8143 |
12 | bb3439269 |
13 | 63a83ba7b |
14 | 369bb9d3b |
15 | 200abe3a3 |
hex | 132025131 |
5133979953 has 12 divisors (see below), whose sum is σ = 7474142208. Its totient is φ = 3395702520.
The previous prime is 5133979951. The next prime is 5133979979. The reversal of 5133979953 is 3599793315.
5133979953 is a `hidden beast` number, since 513 + 3 + 9 + 79 + 9 + 53 = 666.
It is not a de Polignac number, because 5133979953 - 21 = 5133979951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5133979953.
It is not an unprimeable number, because it can be changed into a prime (5133979951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2244693 + ... + 2246978.
It is an arithmetic number, because the mean of its divisors is an integer number (622845184).
Almost surely, 25133979953 is an apocalyptic number.
It is an amenable number.
5133979953 is a deficient number, since it is larger than the sum of its proper divisors (2340162255).
5133979953 is a wasteful number, since it uses less digits than its factorization.
5133979953 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4491804 (or 4491801 counting only the distinct ones).
The product of its digits is 3444525, while the sum is 54.
The square root of 5133979953 is about 71651.7965790112. The cubic root of 5133979953 is about 1725.1150189217.
The spelling of 5133979953 in words is "five billion, one hundred thirty-three million, nine hundred seventy-nine thousand, nine hundred fifty-three".
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