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513400205055121 is a prime number
BaseRepresentation
bin111010010111011110100110…
…0110110011001010010010001
32111022210120200000111102102221
41310232331030312121102101
51014243022104443230441
65015524444225341041
7213065640453530536
oct16456751466312221
92438716600442387
10513400205055121
1113964889348a8aa
12496b8495a97781
131906157c2c4617
1490ac9b9980d8d
153e54ab69858d1
hex1d2ef4cd99491

513400205055121 has 2 divisors, whose sum is σ = 513400205055122. Its totient is φ = 513400205055120.

The previous prime is 513400205055113. The next prime is 513400205055211. The reversal of 513400205055121 is 121550502004315.

Together with next prime (513400205055211) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 501415591920721 + 11984613134400 = 22392311^2 + 3461880^2 .

It is a cyclic number.

It is not a de Polignac number, because 513400205055121 - 23 = 513400205055113 is a prime.

It is not a weakly prime, because it can be changed into another prime (513400205050121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256700102527560 + 256700102527561.

It is an arithmetic number, because the mean of its divisors is an integer number (256700102527561).

Almost surely, 2513400205055121 is an apocalyptic number.

It is an amenable number.

513400205055121 is a deficient number, since it is larger than the sum of its proper divisors (1).

513400205055121 is an equidigital number, since it uses as much as digits as its factorization.

513400205055121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30000, while the sum is 34.

Adding to 513400205055121 its reverse (121550502004315), we get a palindrome (634950707059436).

The spelling of 513400205055121 in words is "five hundred thirteen trillion, four hundred billion, two hundred five million, fifty-five thousand, one hundred twenty-one".