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51340240366001 = 291770353116069
BaseRepresentation
bin10111010110001100101001…
…10010100010100110110001
320201210002010121212010000222
423223012110302202212301
523212124303013203001
6301105214131422425
713546132005522026
oct1353062462424661
9221702117763028
1051340240366001
11153a4301281904
1259120ba754a15
13228549661b272
14c96c4924d54d
155e07266eb61b
hex2eb194ca29b1

51340240366001 has 4 divisors (see below), whose sum is σ = 53110593482100. Its totient is φ = 49569887249904.

The previous prime is 51340240365971. The next prime is 51340240366003. The reversal of 51340240366001 is 10066304204315.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 35273811558976 + 16066428807025 = 5939176^2 + 4008295^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51340240366001 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (51340240366003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885176558006 + ... + 885176558063.

It is an arithmetic number, because the mean of its divisors is an integer number (13277648370525).

Almost surely, 251340240366001 is an apocalyptic number.

It is an amenable number.

51340240366001 is a deficient number, since it is larger than the sum of its proper divisors (1770353116099).

51340240366001 is a wasteful number, since it uses less digits than its factorization.

51340240366001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1770353116098.

The product of its (nonzero) digits is 51840, while the sum is 35.

The spelling of 51340240366001 in words is "fifty-one trillion, three hundred forty billion, two hundred forty million, three hundred sixty-six thousand, one".

Divisors: 1 29 1770353116069 51340240366001