Base | Representation |
---|---|
bin | 10111010110010000010101… |
… | …10011000000110111100001 |
3 | 20201210021020121021011200111 |
4 | 23223020022303000313201 |
5 | 23212142331332421231 |
6 | 301110142414251321 |
7 | 13546232036041021 |
oct | 1353101263006741 |
9 | 221707217234614 |
10 | 51342220201441 |
11 | 153a51278a6544 |
12 | 59125717b6b41 |
13 | 2285720855320 |
14 | c96d96179a81 |
15 | 5e07e04294b1 |
hex | 2eb20acc0de1 |
51342220201441 has 16 divisors (see below), whose sum is σ = 55314535046400. Its totient is φ = 47373180565248.
The previous prime is 51342220201439. The next prime is 51342220201457. The reversal of 51342220201441 is 14410202224315.
It is a cyclic number.
It is not a de Polignac number, because 51342220201441 - 21 = 51342220201439 is a prime.
It is a super-3 number, since 3×513422202014413 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51342220501441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1302454230 + ... + 1302493648.
It is an arithmetic number, because the mean of its divisors is an integer number (3457158440400).
Almost surely, 251342220201441 is an apocalyptic number.
It is an amenable number.
51342220201441 is a deficient number, since it is larger than the sum of its proper divisors (3972314844959).
51342220201441 is a wasteful number, since it uses less digits than its factorization.
51342220201441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78408.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 51342220201441 its reverse (14410202224315), we get a palindrome (65752422425756).
The spelling of 51342220201441 in words is "fifty-one trillion, three hundred forty-two billion, two hundred twenty million, two hundred one thousand, four hundred forty-one".
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