Base | Representation |
---|---|
bin | 111010010111110001010101… |
… | …1110110000100100000101011 |
3 | 2111022221102120000001211121211 |
4 | 1310233202223312010200223 |
5 | 1014244202022044324321 |
6 | 5015555142121413551 |
7 | 213101564036003242 |
oct | 16457425366044053 |
9 | 2438842500054554 |
10 | 513440453511211 |
11 | 139663967707656 |
12 | 4970424903a2b7 |
13 | 190652c4998905 |
14 | 90b0917145959 |
15 | 3e55b701990e1 |
hex | 1d2f8abd8482b |
513440453511211 has 4 divisors (see below), whose sum is σ = 513440645068000. Its totient is φ = 513440261954424.
The previous prime is 513440453511179. The next prime is 513440453511239. The reversal of 513440453511211 is 112115354044315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 513440453511211 - 25 = 513440453511179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (513440433511211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91699971 + ... + 97137868.
It is an arithmetic number, because the mean of its divisors is an integer number (128360161267000).
Almost surely, 2513440453511211 is an apocalyptic number.
513440453511211 is a deficient number, since it is larger than the sum of its proper divisors (191556789).
513440453511211 is a wasteful number, since it uses less digits than its factorization.
513440453511211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 191556788.
The product of its (nonzero) digits is 144000, while the sum is 40.
The spelling of 513440453511211 in words is "five hundred thirteen trillion, four hundred forty billion, four hundred fifty-three million, five hundred eleven thousand, two hundred eleven".
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