Base | Representation |
---|---|
bin | 10111010110010111100101… |
… | …10101010011101101111001 |
3 | 20201210122021220110202222001 |
4 | 23223023302311103231321 |
5 | 23212223314424221144 |
6 | 301112025001101001 |
7 | 13546430356215142 |
oct | 1353136265235571 |
9 | 221718256422861 |
10 | 51346113117049 |
11 | 153a684529a673 |
12 | 5913279487761 |
13 | 2285bc122279a |
14 | c972451b6ac9 |
15 | 5e096c09abd4 |
hex | 2eb2f2d53b79 |
51346113117049 has 2 divisors, whose sum is σ = 51346113117050. Its totient is φ = 51346113117048.
The previous prime is 51346113117037. The next prime is 51346113117127. The reversal of 51346113117049 is 94071131164315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29397075516649 + 21949037600400 = 5421907^2 + 4684980^2 .
It is a cyclic number.
It is not a de Polignac number, because 51346113117049 - 211 = 51346113115001 is a prime.
It is not a weakly prime, because it can be changed into another prime (51346113117149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25673056558524 + 25673056558525.
It is an arithmetic number, because the mean of its divisors is an integer number (25673056558525).
Almost surely, 251346113117049 is an apocalyptic number.
It is an amenable number.
51346113117049 is a deficient number, since it is larger than the sum of its proper divisors (1).
51346113117049 is an equidigital number, since it uses as much as digits as its factorization.
51346113117049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 46.
The spelling of 51346113117049 in words is "fifty-one trillion, three hundred forty-six billion, one hundred thirteen million, one hundred seventeen thousand, forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.300 sec. • engine limits •