Base | Representation |
---|---|
bin | 1110111100100000110… |
… | …10110000001001000001 |
3 | 1211002111101002010210102 |
4 | 13132100122300021001 |
5 | 31403144123242012 |
6 | 1031524254212145 |
7 | 52046414215214 |
oct | 7362032601101 |
9 | 1732441063712 |
10 | 513524040257 |
11 | 188869a2a078 |
12 | 836361b4055 |
13 | 3956ac70c67 |
14 | 1abd740177b |
15 | d55809b2c2 |
hex | 77906b0241 |
513524040257 has 2 divisors, whose sum is σ = 513524040258. Its totient is φ = 513524040256.
The previous prime is 513524040199. The next prime is 513524040307. The reversal of 513524040257 is 752040425315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 499225620481 + 14298419776 = 706559^2 + 119576^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513524040257 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 513524040257.
It is not a weakly prime, because it can be changed into another prime (513524040157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256762020128 + 256762020129.
It is an arithmetic number, because the mean of its divisors is an integer number (256762020129).
Almost surely, 2513524040257 is an apocalyptic number.
It is an amenable number.
513524040257 is a deficient number, since it is larger than the sum of its proper divisors (1).
513524040257 is an equidigital number, since it uses as much as digits as its factorization.
513524040257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168000, while the sum is 38.
The spelling of 513524040257 in words is "five hundred thirteen billion, five hundred twenty-four million, forty thousand, two hundred fifty-seven".
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