Base | Representation |
---|---|
bin | 111010011000011101000011… |
… | …0010001000011100101101111 |
3 | 2111100021101211011222221012222 |
4 | 1310300322012101003211233 |
5 | 1014302221232424103011 |
6 | 5020110223425545555 |
7 | 213111425662551143 |
oct | 16460720621034557 |
9 | 2440241734887188 |
10 | 513534312331631 |
11 | 13969a751554628 |
12 | 4971a4821a52bb |
13 | 190711020ab386 |
14 | 90b529c727223 |
15 | 3e583151aeddb |
hex | 1d30e8644396f |
513534312331631 has 16 divisors (see below), whose sum is σ = 525600051744768. Its totient is φ = 501474180060000.
The previous prime is 513534312331589. The next prime is 513534312331639. The reversal of 513534312331631 is 136133213435315.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513534312331631 is a prime.
It is a super-2 number, since 2×5135343123316312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (513534312331639) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4000951106 + ... + 4001079456.
It is an arithmetic number, because the mean of its divisors is an integer number (32850003234048).
Almost surely, 2513534312331631 is an apocalyptic number.
513534312331631 is a deficient number, since it is larger than the sum of its proper divisors (12065739413137).
513534312331631 is a wasteful number, since it uses less digits than its factorization.
513534312331631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149462.
The product of its digits is 874800, while the sum is 44.
Adding to 513534312331631 its reverse (136133213435315), we get a palindrome (649667525766946).
The spelling of 513534312331631 in words is "five hundred thirteen trillion, five hundred thirty-four billion, three hundred twelve million, three hundred thirty-one thousand, six hundred thirty-one".
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