Base | Representation |
---|---|
bin | 1110111100100010110… |
… | …00001000100110001011 |
3 | 1211002112111100122102200 |
4 | 13132101120020212023 |
5 | 31403212233144321 |
6 | 1031530031131243 |
7 | 52050001043502 |
oct | 7362130104613 |
9 | 1732474318380 |
10 | 513540131211 |
11 | 18887801a488 |
12 | 8363b673b23 |
13 | 395713b6033 |
14 | 1abd95cd839 |
15 | d5596c8d26 |
hex | 779160898b |
513540131211 has 6 divisors (see below), whose sum is σ = 741780189540. Its totient is φ = 342360087468.
The previous prime is 513540131201. The next prime is 513540131243. The reversal of 513540131211 is 112131045315.
513540131211 is a `hidden beast` number, since 5 + 13 + 5 + 401 + 31 + 211 = 666.
It is not a de Polignac number, because 513540131211 - 25 = 513540131179 is a prime.
It is a super-2 number, since 2×5135401312112 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (513540131201) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 28530007281 + ... + 28530007298.
It is an arithmetic number, because the mean of its divisors is an integer number (123630031590).
Almost surely, 2513540131211 is an apocalyptic number.
513540131211 is a deficient number, since it is larger than the sum of its proper divisors (228240058329).
513540131211 is a wasteful number, since it uses less digits than its factorization.
513540131211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57060014585 (or 57060014582 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
Adding to 513540131211 its reverse (112131045315), we get a palindrome (625671176526).
The spelling of 513540131211 in words is "five hundred thirteen billion, five hundred forty million, one hundred thirty-one thousand, two hundred eleven".
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