Base | Representation |
---|---|
bin | 1110111100110001100… |
… | …01110101101100100011 |
3 | 1211002212011000120202222 |
4 | 13132120301311230203 |
5 | 31403441030410201 |
6 | 1031550224501255 |
7 | 52053036411104 |
oct | 7363061655443 |
9 | 1732764016688 |
10 | 513664310051 |
11 | 188931125922 |
12 | 8367517a82b |
13 | 39591044039 |
14 | 1ac0bcb63ab |
15 | d56555791b |
hex | 7798c75b23 |
513664310051 has 4 divisors (see below), whose sum is σ = 513668250000. Its totient is φ = 513660370104.
The previous prime is 513664310039. The next prime is 513664310113. The reversal of 513664310051 is 150013466315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513664310051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 513664309993 and 513664310020.
It is not an unprimeable number, because it can be changed into a prime (513664310651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1767476 + ... + 2037473.
It is an arithmetic number, because the mean of its divisors is an integer number (128417062500).
Almost surely, 2513664310051 is an apocalyptic number.
513664310051 is a deficient number, since it is larger than the sum of its proper divisors (3939949).
513664310051 is a wasteful number, since it uses less digits than its factorization.
513664310051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3939948.
The product of its (nonzero) digits is 32400, while the sum is 35.
Adding to 513664310051 its reverse (150013466315), we get a palindrome (663677776366).
The spelling of 513664310051 in words is "five hundred thirteen billion, six hundred sixty-four million, three hundred ten thousand, fifty-one".
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