Base | Representation |
---|---|
bin | 100101011000010111000… |
… | …0011000000000000110001 |
3 | 200012010220221011002102111 |
4 | 1022300232003000000301 |
5 | 1133133202134040213 |
6 | 14532054235445321 |
7 | 1040114235402103 |
oct | 112605603000061 |
9 | 20163827132374 |
10 | 5137553424433 |
11 | 1700907a77221 |
12 | 6ab8382b6841 |
13 | 2b3613b10ac1 |
14 | 13a9320ad573 |
15 | 8d98d76ba3d |
hex | 4ac2e0c0031 |
5137553424433 has 2 divisors, whose sum is σ = 5137553424434. Its totient is φ = 5137553424432.
The previous prime is 5137553424413. The next prime is 5137553424611. The reversal of 5137553424433 is 3344243557315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5121381724209 + 16171700224 = 2263047^2 + 127168^2 .
It is a cyclic number.
It is not a de Polignac number, because 5137553424433 - 29 = 5137553423921 is a prime.
It is not a weakly prime, because it can be changed into another prime (5137553424413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2568776712216 + 2568776712217.
It is an arithmetic number, because the mean of its divisors is an integer number (2568776712217).
Almost surely, 25137553424433 is an apocalyptic number.
It is an amenable number.
5137553424433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5137553424433 is an equidigital number, since it uses as much as digits as its factorization.
5137553424433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9072000, while the sum is 49.
The spelling of 5137553424433 in words is "five trillion, one hundred thirty-seven billion, five hundred fifty-three million, four hundred twenty-four thousand, four hundred thirty-three".
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