Base | Representation |
---|---|
bin | 10111010111010001001010… |
… | …00010101011000110111011 |
3 | 20201220121001212200221101021 |
4 | 23223220211002223012323 |
5 | 23213230114141040403 |
6 | 301134135520203311 |
7 | 13551603312432103 |
oct | 1353504502530673 |
9 | 221817055627337 |
10 | 51377020252603 |
11 | 1540896559a001 |
12 | 5919264169537 |
13 | 2288aa850c086 |
14 | c98937cb8203 |
15 | 5e167a6608bd |
hex | 2eba250ab1bb |
51377020252603 has 2 divisors, whose sum is σ = 51377020252604. Its totient is φ = 51377020252602.
The previous prime is 51377020252583. The next prime is 51377020252661. The reversal of 51377020252603 is 30625202077315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51377020252603 - 29 = 51377020252091 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51377020252603.
It is not a weakly prime, because it can be changed into another prime (51377020252303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25688510126301 + 25688510126302.
It is an arithmetic number, because the mean of its divisors is an integer number (25688510126302).
Almost surely, 251377020252603 is an apocalyptic number.
51377020252603 is a deficient number, since it is larger than the sum of its proper divisors (1).
51377020252603 is an equidigital number, since it uses as much as digits as its factorization.
51377020252603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 529200, while the sum is 43.
The spelling of 51377020252603 in words is "fifty-one trillion, three hundred seventy-seven billion, twenty million, two hundred fifty-two thousand, six hundred three".
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