Base | Representation |
---|---|
bin | 100101011000101010100… |
… | …1010111011100110101001 |
3 | 200012012121200021011221111 |
4 | 1022301111022323212221 |
5 | 1133141023203034303 |
6 | 14532243324310321 |
7 | 1040136425543065 |
oct | 112612512734651 |
9 | 20165550234844 |
10 | 5138209814953 |
11 | 1701114540126 |
12 | 6ab9a00a23a1 |
13 | 2b36b9ac1767 |
14 | 13a995334aa5 |
15 | 8d9cb1c7b6d |
hex | 4ac552bb9a9 |
5138209814953 has 2 divisors, whose sum is σ = 5138209814954. Its totient is φ = 5138209814952.
The previous prime is 5138209814909. The next prime is 5138209814957. The reversal of 5138209814953 is 3594189028315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4835812106304 + 302397708649 = 2199048^2 + 549907^2 .
It is a cyclic number.
It is not a de Polignac number, because 5138209814953 - 233 = 5129619880361 is a prime.
It is not a weakly prime, because it can be changed into another prime (5138209814957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2569104907476 + 2569104907477.
It is an arithmetic number, because the mean of its divisors is an integer number (2569104907477).
Almost surely, 25138209814953 is an apocalyptic number.
It is an amenable number.
5138209814953 is a deficient number, since it is larger than the sum of its proper divisors (1).
5138209814953 is an equidigital number, since it uses as much as digits as its factorization.
5138209814953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9331200, while the sum is 58.
The spelling of 5138209814953 in words is "five trillion, one hundred thirty-eight billion, two hundred nine million, eight hundred fourteen thousand, nine hundred fifty-three".
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