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5140101120211 = 34914728083439
BaseRepresentation
bin100101011001100010111…
…1001101100000011010011
3200012101111111002110000101
41022303011321230003103
51133203411341321321
614533155125433231
71040234332430431
oct112630571540323
920171444073011
105140101120211
1117019a5097822
126b022956b817
132b392b89c8b5
1413aad45b7d51
158da8c269791
hex4acc5e6c0d3

5140101120211 has 4 divisors (see below), whose sum is σ = 5154829204000. Its totient is φ = 5125373036424.

The previous prime is 5140101120127. The next prime is 5140101120257. The reversal of 5140101120211 is 1120211010415.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5140101120211 - 213 = 5140101112019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5140101160211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7364041371 + ... + 7364042068.

It is an arithmetic number, because the mean of its divisors is an integer number (1288707301000).

Almost surely, 25140101120211 is an apocalyptic number.

5140101120211 is a deficient number, since it is larger than the sum of its proper divisors (14728083789).

5140101120211 is a wasteful number, since it uses less digits than its factorization.

5140101120211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14728083788.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 5140101120211 its reverse (1120211010415), we get a palindrome (6260312130626).

The spelling of 5140101120211 in words is "five trillion, one hundred forty billion, one hundred one million, one hundred twenty thousand, two hundred eleven".

Divisors: 1 349 14728083439 5140101120211