Base | Representation |
---|---|
bin | 111010011011111100001001… |
… | …1100000000110010011111011 |
3 | 2111101222012111020200110011002 |
4 | 1310313320103200012103323 |
5 | 1014333043442321413001 |
6 | 5021114301243155215 |
7 | 213161146542165245 |
oct | 16467702340062373 |
9 | 2441865436613132 |
10 | 514013423232251 |
11 | 139864961126528 |
12 | 497972b3515b0b |
13 | 190a73475a35c7 |
14 | 90d054d545095 |
15 | 3e65a06ea046b |
hex | 1d37e138064fb |
514013423232251 has 2 divisors, whose sum is σ = 514013423232252. Its totient is φ = 514013423232250.
The previous prime is 514013423232223. The next prime is 514013423232259. The reversal of 514013423232251 is 152232324310415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 514013423232251 - 210 = 514013423231227 is a prime.
It is not a weakly prime, because it can be changed into another prime (514013423232259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257006711616125 + 257006711616126.
It is an arithmetic number, because the mean of its divisors is an integer number (257006711616126).
Almost surely, 2514013423232251 is an apocalyptic number.
514013423232251 is a deficient number, since it is larger than the sum of its proper divisors (1).
514013423232251 is an equidigital number, since it uses as much as digits as its factorization.
514013423232251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 514013423232251 its reverse (152232324310415), we get a palindrome (666245747542666).
The spelling of 514013423232251 in words is "five hundred fourteen trillion, thirteen billion, four hundred twenty-three million, two hundred thirty-two thousand, two hundred fifty-one".
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