Base | Representation |
---|---|
bin | 11110101000110… |
… | …011110100010001 |
3 | 1022211012122022101 |
4 | 132220303310101 |
5 | 2023041430411 |
6 | 123001040401 |
7 | 15511023331 |
oct | 3650636421 |
9 | 1284178271 |
10 | 514014481 |
11 | 244169762 |
12 | 124186101 |
13 | 82650ca6 |
14 | 4c3a30c1 |
15 | 301d58c1 |
hex | 1ea33d11 |
514014481 has 2 divisors, whose sum is σ = 514014482. Its totient is φ = 514014480.
The previous prime is 514014463. The next prime is 514014491. The reversal of 514014481 is 184410415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 433014481 + 81000000 = 20809^2 + 9000^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-514014481 is a prime.
It is a super-2 number, since 2×5140144812 = 528421773355398722, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (514014491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257007240 + 257007241.
It is an arithmetic number, because the mean of its divisors is an integer number (257007241).
Almost surely, 2514014481 is an apocalyptic number.
It is an amenable number.
514014481 is a deficient number, since it is larger than the sum of its proper divisors (1).
514014481 is an equidigital number, since it uses as much as digits as its factorization.
514014481 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 28.
The square root of 514014481 is about 22671.8874600241. The cubic root of 514014481 is about 801.0478358051.
Adding to 514014481 its reverse (184410415), we get a palindrome (698424896).
The spelling of 514014481 in words is "five hundred fourteen million, fourteen thousand, four hundred eighty-one".
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