Base | Representation |
---|---|
bin | 1110111101011100000… |
… | …10111110100100110001 |
3 | 1211010210000102122001021 |
4 | 13132232002332210301 |
5 | 31410203401440101 |
6 | 1032045452335441 |
7 | 52064631316141 |
oct | 7365602764461 |
9 | 1733700378037 |
10 | 514021124401 |
11 | 188aa4584814 |
12 | 83754774581 |
13 | 39619c44aa5 |
14 | 1ac43438921 |
15 | d586a3a5a1 |
hex | 77ae0be931 |
514021124401 has 2 divisors, whose sum is σ = 514021124402. Its totient is φ = 514021124400.
The previous prime is 514021124371. The next prime is 514021124417. The reversal of 514021124401 is 104421120415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 483234912801 + 30786211600 = 695151^2 + 175460^2 .
It is a cyclic number.
It is not a de Polignac number, because 514021124401 - 225 = 513987569969 is a prime.
It is not a weakly prime, because it can be changed into another prime (514021134401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257010562200 + 257010562201.
It is an arithmetic number, because the mean of its divisors is an integer number (257010562201).
Almost surely, 2514021124401 is an apocalyptic number.
It is an amenable number.
514021124401 is a deficient number, since it is larger than the sum of its proper divisors (1).
514021124401 is an equidigital number, since it uses as much as digits as its factorization.
514021124401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 514021124401 its reverse (104421120415), we get a palindrome (618442244816).
The spelling of 514021124401 in words is "five hundred fourteen billion, twenty-one million, one hundred twenty-four thousand, four hundred one".
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