Base | Representation |
---|---|
bin | 1110111101011101100… |
… | …11001110110111100011 |
3 | 1211010210220020022002211 |
4 | 13132232303032313203 |
5 | 31410220121232201 |
6 | 1032051023422551 |
7 | 52065143662450 |
oct | 7365663166743 |
9 | 1733726208084 |
10 | 514033774051 |
11 | 189000734676 |
12 | 83758a54a57 |
13 | 3961c7536a5 |
14 | 1ac44dac827 |
15 | d587bd8651 |
hex | 77aeccede3 |
514033774051 has 4 divisors (see below), whose sum is σ = 587467170352. Its totient is φ = 440600377752.
The previous prime is 514033774039. The next prime is 514033774069. The reversal of 514033774051 is 150477330415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 514033774051 - 25 = 514033774019 is a prime.
It is a super-3 number, since 3×5140337740513 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 514033773995 and 514033774013.
It is not an unprimeable number, because it can be changed into a prime (514033774151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36716698140 + ... + 36716698153.
It is an arithmetic number, because the mean of its divisors is an integer number (146866792588).
Almost surely, 2514033774051 is an apocalyptic number.
514033774051 is a deficient number, since it is larger than the sum of its proper divisors (73433396301).
514033774051 is an equidigital number, since it uses as much as digits as its factorization.
514033774051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73433396300.
The product of its (nonzero) digits is 176400, while the sum is 40.
The spelling of 514033774051 in words is "five hundred fourteen billion, thirty-three million, seven hundred seventy-four thousand, fifty-one".
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