Base | Representation |
---|---|
bin | 1110111101101000011… |
… | …11100111100100011011 |
3 | 1211011001021002012120222 |
4 | 13132310033213210123 |
5 | 31410412011220324 |
6 | 1032104045110255 |
7 | 52100333153663 |
oct | 7366417474433 |
9 | 1734037065528 |
10 | 514125101339 |
11 | 189048242173 |
12 | 8378355838b |
13 | 3963564b7c5 |
14 | 1ac531831a3 |
15 | d590c2855e |
hex | 77b43e791b |
514125101339 has 2 divisors, whose sum is σ = 514125101340. Its totient is φ = 514125101338.
The previous prime is 514125101299. The next prime is 514125101363. The reversal of 514125101339 is 933101521415.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-514125101339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 514125101299 and 514125101308.
It is not a weakly prime, because it can be changed into another prime (514125101839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257062550669 + 257062550670.
It is an arithmetic number, because the mean of its divisors is an integer number (257062550670).
Almost surely, 2514125101339 is an apocalyptic number.
514125101339 is a deficient number, since it is larger than the sum of its proper divisors (1).
514125101339 is an equidigital number, since it uses as much as digits as its factorization.
514125101339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 514125101339 in words is "five hundred fourteen billion, one hundred twenty-five million, one hundred one thousand, three hundred thirty-nine".
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