Base | Representation |
---|---|
bin | 101111111001100011… |
… | …000000101101101011 |
3 | 11220202100011000211202 |
4 | 233321203000231223 |
5 | 1320312411020003 |
6 | 35343252114415 |
7 | 3500342135153 |
oct | 577143005553 |
9 | 156670130752 |
10 | 51431345003 |
11 | 1a8a2720805 |
12 | 9b74305a0b |
13 | 4b0847472c |
14 | 26bc881763 |
15 | 151037c088 |
hex | bf98c0b6b |
51431345003 has 4 divisors (see below), whose sum is σ = 51476030208. Its totient is φ = 51386659800.
The previous prime is 51431344999. The next prime is 51431345123. The reversal of 51431345003 is 30054313415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51431345003 - 22 = 51431344999 is a prime.
It is a super-2 number, since 2×514313450032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51431315003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22340876 + ... + 22343177.
It is an arithmetic number, because the mean of its divisors is an integer number (12869007552).
Almost surely, 251431345003 is an apocalyptic number.
51431345003 is a deficient number, since it is larger than the sum of its proper divisors (44685205).
51431345003 is a wasteful number, since it uses less digits than its factorization.
51431345003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44685204.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 51431345003 its reverse (30054313415), we get a palindrome (81485658418).
The spelling of 51431345003 in words is "fifty-one billion, four hundred thirty-one million, three hundred forty-five thousand, three".
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