51433230113 has 4 divisors (see below), whose sum is σ = 51433772208. Its totient is φ = 51432688020.

The previous prime is 51433230103. The next prime is 51433230143. The reversal of 51433230113 is 31103233415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 51433230113 - 2¹² = 51433226017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (51433230103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87131 + ... + 332352.

It is an arithmetic number, because the mean of its divisors is an integer number (12858443052).

Almost surely, 2^51433230113 is an apocalyptic number.

It is an amenable number.

51433230113 is a deficient number, since it is larger than the sum of its proper divisors (542095).

51433230113 is a wasteful number, since it uses less digits than its factorization.

51433230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 542094.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 51433230113 its reverse (31103233415), we get a palindrome (82536463528).

It can be divided in two parts, 514332 and 30113, that added together give a palindrome (544445).

The spelling of 51433230113 in words is "fifty-one billion, four hundred thirty-three million, two hundred thirty thousand, one hundred thirteen".