514342019 has 2 divisors, whose sum is σ = 514342020. Its totient is φ = 514342018.

The previous prime is 514341973. The next prime is 514342079. The reversal of 514342019 is 910243415.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-514342019 is a prime.

It is a super-2 number, since 2×514342019² = 529095425017992722, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 514341982 and 514342000.

It is not a weakly prime, because it can be changed into another prime (514342079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257171009 + 257171010.

It is an arithmetic number, because the mean of its divisors is an integer number (257171010).

Almost surely, 2^514342019 is an apocalyptic number.

514342019 is a deficient number, since it is larger than the sum of its proper divisors (1).

514342019 is an equidigital number, since it uses as much as digits as its factorization.

514342019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

The square root of 514342019 is about 22679.1097488416. The cubic root of 514342019 is about 801.2179463798.

The spelling of 514342019 in words is "five hundred fourteen million, three hundred forty-two thousand, nineteen".