Base | Representation |
---|---|
bin | 1001100101001001… |
… | …01000011101010001 |
3 | 111021110021100220012 |
4 | 10302210220131101 |
5 | 41013204242433 |
6 | 2210213324305 |
7 | 241313304431 |
oct | 46244503521 |
9 | 14243240805 |
10 | 5143430993 |
11 | 21aa372918 |
12 | bb6636695 |
13 | 63c79a7bc |
14 | 36b15a2c1 |
15 | 201839848 |
hex | 132928751 |
5143430993 has 2 divisors, whose sum is σ = 5143430994. Its totient is φ = 5143430992.
The previous prime is 5143430989. The next prime is 5143431037. The reversal of 5143430993 is 3990343415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4554495169 + 588935824 = 67487^2 + 24268^2 .
It is a cyclic number.
It is not a de Polignac number, because 5143430993 - 22 = 5143430989 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5143430993.
It is not a weakly prime, because it can be changed into another prime (5143430953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571715496 + 2571715497.
It is an arithmetic number, because the mean of its divisors is an integer number (2571715497).
Almost surely, 25143430993 is an apocalyptic number.
It is an amenable number.
5143430993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5143430993 is an equidigital number, since it uses as much as digits as its factorization.
5143430993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 41.
The square root of 5143430993 is about 71717.7174274251. The cubic root of 5143430993 is about 1726.1729464794.
The spelling of 5143430993 in words is "five billion, one hundred forty-three million, four hundred thirty thousand, nine hundred ninety-three".
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