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51435242451041 = 192707118023739
BaseRepresentation
bin10111011000111101100110…
…10110101111000001100001
320202010011100111001001212012
423230132303112233001201
523220203334031413131
6301221005120042305
713556034154105631
oct1354366326570141
9222104314031765
1051435242451041
11154306224a4479
1259285b2763395
13229142684c177
14c9b69c5d26c1
155e2e36c9252b
hex2ec7b35af061

51435242451041 has 4 divisors (see below), whose sum is σ = 54142360474800. Its totient is φ = 48728124427284.

The previous prime is 51435242451031. The next prime is 51435242451053. The reversal of 51435242451041 is 14015424253415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51435242451041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 51435242451041.

It is not an unprimeable number, because it can be changed into a prime (51435242451031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1353559011851 + ... + 1353559011888.

It is an arithmetic number, because the mean of its divisors is an integer number (13535590118700).

Almost surely, 251435242451041 is an apocalyptic number.

It is an amenable number.

51435242451041 is a deficient number, since it is larger than the sum of its proper divisors (2707118023759).

51435242451041 is a wasteful number, since it uses less digits than its factorization.

51435242451041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2707118023758.

The product of its (nonzero) digits is 384000, while the sum is 41.

The spelling of 51435242451041 in words is "fifty-one trillion, four hundred thirty-five billion, two hundred forty-two million, four hundred fifty-one thousand, forty-one".

Divisors: 1 19 2707118023739 51435242451041