5143712641 has 4 divisors (see below), whose sum is σ = 5214174532. Its totient is φ = 5073250752.

The previous prime is 5143712611. The next prime is 5143712701. The reversal of 5143712641 is 1462173415.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1287302641 + 3856410000 = 35879^2 + 62100^2 .

It is a cyclic number.

It is not a de Polignac number, because 5143712641 - 2¹⁵ = 5143679873 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5143712597 and 5143712606.

It is not an unprimeable number, because it can be changed into a prime (5143712611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35230836 + ... + 35230981.

It is an arithmetic number, because the mean of its divisors is an integer number (1303543633).

Almost surely, 2^5143712641 is an apocalyptic number.

It is an amenable number.

5143712641 is a deficient number, since it is larger than the sum of its proper divisors (70461891).

5143712641 is an equidigital number, since it uses as much as digits as its factorization.

5143712641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70461890.

The product of its digits is 20160, while the sum is 34.

The square root of 5143712641 is about 71719.6809878572. The cubic root of 5143712641 is about 1726.2044536118.

The spelling of 5143712641 in words is "five billion, one hundred forty-three million, seven hundred twelve thousand, six hundred forty-one".