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51441335040001 = 166913081980411
BaseRepresentation
bin10111011001001000111101…
…00000000111100000000001
320202010202002002022122201011
423230210132200013200001
523220303323232240001
6301223453441240521
713556341144211644
oct1354443640074001
9222122062278634
1051441335040001
1115433169614765
125929813033141
132291b87b653aa
14c9bab9823a5b
155e3191ab8d51
hex2ec91e807801

51441335040001 has 4 divisors (see below), whose sum is σ = 51444417037104. Its totient is φ = 51438253042900.

The previous prime is 51441335039999. The next prime is 51441335040049. The reversal of 51441335040001 is 10004053314415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51441335040001 - 21 = 51441335039999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51441335040701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1540973515 + ... + 1541006896.

It is an arithmetic number, because the mean of its divisors is an integer number (12861104259276).

Almost surely, 251441335040001 is an apocalyptic number.

It is an amenable number.

51441335040001 is a deficient number, since it is larger than the sum of its proper divisors (3081997103).

51441335040001 is a wasteful number, since it uses less digits than its factorization.

51441335040001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3081997102.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 51441335040001 its reverse (10004053314415), we get a palindrome (61445388354416).

The spelling of 51441335040001 in words is "fifty-one trillion, four hundred forty-one billion, three hundred thirty-five million, forty thousand, one".

Divisors: 1 16691 3081980411 51441335040001