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5144203312251 = 31714734437417
BaseRepresentation
bin100101011011011101001…
…1010010011110001111011
3200012210002101002101120220
41022312322122103301323
51133240312021443001
614535114145551123
71040441103456123
oct112667232236173
920183071071526
105144203312251
11170370a72a383
126b0b933454a3
132b4133721773
1413ada332dc83
158dc2c478c36
hex4adba693c7b

5144203312251 has 4 divisors (see below), whose sum is σ = 6858937749672. Its totient is φ = 3429468874832.

The previous prime is 5144203312247. The next prime is 5144203312273. The reversal of 5144203312251 is 1522133024415.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5144203312251 - 22 = 5144203312247 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5144203312051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857367218706 + ... + 857367218711.

It is an arithmetic number, because the mean of its divisors is an integer number (1714734437418).

Almost surely, 25144203312251 is an apocalyptic number.

5144203312251 is a deficient number, since it is larger than the sum of its proper divisors (1714734437421).

5144203312251 is a wasteful number, since it uses less digits than its factorization.

5144203312251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1714734437420.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 5144203312251 its reverse (1522133024415), we get a palindrome (6666336336666).

The spelling of 5144203312251 in words is "five trillion, one hundred forty-four billion, two hundred three million, three hundred twelve thousand, two hundred fifty-one".

Divisors: 1 3 1714734437417 5144203312251