Base | Representation |
---|---|
bin | 100101011011100000100… |
… | …0001000011111000101011 |
3 | 200012210101002121201112022 |
4 | 1022313001001003320223 |
5 | 1133241023404242214 |
6 | 14535133145135055 |
7 | 1040443620442562 |
oct | 112670101037053 |
9 | 20183332551468 |
10 | 5144314134059 |
11 | 1703767242451 |
12 | 6b100448a48b |
13 | 2b4150683bb9 |
14 | 13adb3d3abd9 |
15 | 8dc37069d8e |
hex | 4adc1043e2b |
5144314134059 has 2 divisors, whose sum is σ = 5144314134060. Its totient is φ = 5144314134058.
The previous prime is 5144314133989. The next prime is 5144314134083. The reversal of 5144314134059 is 9504314134415.
5144314134059 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5144314134059 - 212 = 5144314129963 is a prime.
It is not a weakly prime, because it can be changed into another prime (5144314133059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2572157067029 + 2572157067030.
It is an arithmetic number, because the mean of its divisors is an integer number (2572157067030).
Almost surely, 25144314134059 is an apocalyptic number.
5144314134059 is a deficient number, since it is larger than the sum of its proper divisors (1).
5144314134059 is an equidigital number, since it uses as much as digits as its factorization.
5144314134059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 44.
The spelling of 5144314134059 in words is "five trillion, one hundred forty-four billion, three hundred fourteen million, one hundred thirty-four thousand, fifty-nine".
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